Functions
NPY_NO_EXPORT void	PyArray_DatetimeToDatetimeStruct (npy_datetime val, NPY_DATETIMEUNIT fr, npy_datetimestruct *result)
NPY_NO_EXPORT void	PyArray_TimedeltaToTimedeltaStruct (npy_timedelta val, NPY_DATETIMEUNIT fr, npy_timedeltastruct *result)
NPY_NO_EXPORT npy_datetime	PyArray_DatetimeStructToDatetime (NPY_DATETIMEUNIT fr, npy_datetimestruct *d)
NPY_NO_EXPORT npy_datetime	PyArray_TimedeltaStructToTimedelta (NPY_DATETIMEUNIT fr, npy_timedeltastruct *d)

Function Documentation

NPY_NO_EXPORT npy_datetime PyArray_DatetimeStructToDatetime	(	NPY_DATETIMEUNIT	fr,
		npy_datetimestruct *	d
	)

== End of section adapted from mx.DateTime ==

System Message: SEVERE/4 (<string>, line 1)

Missing matching underline for section title overline.

==================================================
Parsing DateTime struct and returns a date-time number
=================================================

<blockquote> Structure is assumed to be already normalized</blockquote>

Create a datetime value from a filled datetime struct and resolution unit.

<

The absolute number of days since Jan 1, 1970

This is just 7-days for now.

Invalid business day

offset to adjust first week

only 2.6 hours

get number of seconds as a postive or negative number

only 9.2 secs

Shouldn't get here

NPY_NO_EXPORT void PyArray_DatetimeToDatetimeStruct	(	npy_datetime	val,
		NPY_DATETIMEUNIT	fr,
		npy_datetimestruct *	result
	)

Fill the datetime struct from the value and resolution unit.

Note that what looks like val / N and val % N for positive numbers maps to [val - (N-1)] / N and [N-1 + (val+1) % N] for negative numbers (with the 2nd value, the remainder, being positive in both cases).

A week is the same as 7 days

Number of business days since Thursday, 1-1-70

A buisness day is M T W Th F (i.e. all but Sat and Sun.) Convert the business day to the number of actual days.

Must convert [0,1,2,3,4,5,6,7,...] to: [0,1,4,5,6,7,8,11,...]
and [...,-9,-8,-7,-6,-5,-4,-3,-2,-1,0] to: [...,-13,-10,-9,-8,-7,-6,-3,-2,-1,0]

Recall how C computes / and % with negative numbers

entire range is only += 2.6 hours

tmp (number of fs) will be positive after this segment

we are at the last second

entire range is only += 9.2 seconds

NPY_NO_EXPORT npy_datetime PyArray_TimedeltaStructToTimedelta	(	NPY_DATETIMEUNIT	fr,
		npy_timedeltastruct *	d
	)

Create a timdelta value from a filled timedelta struct and resolution unit.

This is just 7-days for now.

What is the meaning of a relative Business day?

This assumes you want to take the day difference and convert it to business-day difference (removing 2 every 7).

only 2.6 hours

only 9.2 secs

Shouldn't get here

References ymdstruct::day, days_to_ymdstruct(), hmsstruct::hour, hmsstruct::min, ymdstruct::month, NPY_FR_B, NPY_FR_D, NPY_FR_h, NPY_FR_m, NPY_FR_M, NPY_FR_s, NPY_FR_W, NPY_FR_Y, hmsstruct::sec, seconds_to_hmsstruct(), and ymdstruct::year.

NPY_NO_EXPORT void PyArray_TimedeltaToTimedeltaStruct	(	npy_timedelta	val,
		NPY_DATETIMEUNIT	fr,
		npy_timedeltastruct *	result
	)

FIXME: Overflow is not handled at all: To convert from Years, Months, and Business Days, multiplication by the average is done

Fill the timedelta struct from the timedelta value and resolution unit.

Note that what looks like val / N and val % N for positive numbers maps to [val - (N-1)] / N and [N-1 + (val+1) % N] for negative numbers (with the 2nd value, the remainder, being positive in both cases).

Number of business days since Thursday, 1-1-70

entire range is only += 9.2 hours

entire range is only += 2.6 seconds

Functions

Function Documentation

== End of section adapted from mx.DateTime ==