in_array
(PHP 4 , PHP 5)
in_array -- Return
TRUE if a value exists in an array
Description
bool
in_array ( mixed needle, array haystack [, bool strict])
Searches haystack for
needle and returns TRUE
if it is found in the array, FALSE otherwise.
If the third parameter strict is set to
TRUE then the in_array() function
will also check the types of
the needle in the haystack.
Notã:
If needle is a string, the comparison is done in
a case-sensitive manner.
Notã:
In PHP versions before 4.2.0 needle was not
allowed to be an array.
Exemplu 1. in_array() example
$os = array ("Mac", "NT", "Irix", "Linux"); if (in_array ("Irix", $os)) { print "Got Irix"; } if (in_array ("mac", $os)) { print "Got mac"; }
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The second condition fails because in_array()
is case-sensitive, so the program above will display:
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Exemplu 2. in_array() with strict example
<?php $a = array('1.10', 12.4, 1.13);
if (in_array('12.4', $a, TRUE)) echo "'12.4' found with strict check\n"; if (in_array(1.13, $a, TRUE)) echo "1.13 found with strict check\n"; ?>
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This will display:
1.13 found with strict check
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Exemplu 3. in_array() with an array as needle
<?php $a = array(array('p', 'h'), array('p', 'r'), 'o');
if (in_array(array ('p', 'h'), $a)) echo "'ph' is found\n"; if (in_array(array ('f', 'i'), $a)) echo "'fi' is not found\n"; if (in_array('o', $a)) echo "'o' is found\n"; ?>
// This will output:
'ph' is found 'o' is found
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See also array_search().