PHP Manuál | ||
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Predchádzajúci | Kapitola 15. References Explained | Nasledujúci |
As said before, references aren't pointers. That means, the following construct won't do what you expect:
What happens is that $var in foo will be bound with $bar in caller, but then it will be re-bound with $GLOBALS["baz"]. There's no way to bind $bar in the calling scope to something else using the reference mechanism, since $bar is not available in the function foo (it is represented by $var, but $var has only variable contents and not name-to-value binding in the calling symbol table).
Predchádzajúci | Domov | Nasledujúci |
What References Do | Hore | Passing by Reference |